6x^2-32x-280=0

Solution for 6x^2-32x-280=0 equation:

6x^2-32x-280=0

a = 6; b = -32; c = -280;
Δ = b2-4ac
Δ = -322-4·6·(-280)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-88}{2*6}=\frac{-56}{12}
=-4+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+88}{2*6}=\frac{120}{12}
=10
$